两直线的交点在线计算器
直线1:A x+B 1 y+C 1 =0,直线2:A 2 x+B 2 y+C 2 =0,则两直线交点求法为:
x=(B 1 C 2 -B 2 C 1 )/(B 2 A -B 1 A 2 ) y=(A C 2 -C 1 A 2 )/(B 1 A 2 -A B 2 )
直线1:A x+B 1 y+C 1 =0,直线2:A 2 x+B 2 y+C 2 =0,则两直线交点求法为:
x=(B 1 C 2 -B 2 C 1 )/(B 2 A -B 1 A 2 ) y=(A C 2 -C 1 A 2 )/(B 1 A 2 -A B 2 )